Question

1. Consider the decomposition reaction of sodium chlorate. There are 100 grams of
sodium chlorate.
A. What are the products of this reaction?
B. Write the full balanced chemical reaction.
C. How many moles of sodium chlorate are available to react?
D. How many moles of sodium chloride will be produced?
E. How many grams of sodium chloride will be produced?
F. How many moles of oxygen gas will be produced?
G. How many grams of oxygen gas will be produced?
H. If 10 grams of oxygen gas are produced when the reaction takes place in the
lab, what is the percent yield?

Answer 1

A. NaCl(s) and O2(g)

B. 2NaClO3(s) —> 2NaCl(s) + 3O2(g)

C. moles NaClO3 = 100 g / 106.44 g/mol = 0.939 mol NaClO3

D. 0.939 mol NaCl (because the NaClO3 and NaCl are in a 1 to 1 ratio)

E. grams NaCl = 0.939 mol • 58.44 g/mol = 54.9 g NaCl

F. moles of O2 = 0.939 mol NaClO3 • (3 mol O2 / 2 mol NaClO3) = 1.41 mol O2

G. grams of O2 = 1.41 mol • 32 g/mol = 45.1 g O2

H. Percent yield = 10/45.1 • 100% = 22.2% yield