Question

A body of mass 11 kg is subjected to a net force of 20 N East for 30 s. Calculate the change in
velocity of the body.

Answer 1

Answer:

54.55 m/s

Explanation:

From the question above,

Change in velocity = impulse/mass

Δv = I/m = Ft/m................... Equation 1

Where F = force, t = time, m = mass

Given: F = 20 N, t = 30 s, m = 11 kg

Substitute these values into equation 1

Δv = (20×30)/11

Δv = 600/11

Δv = 54.55 m/s

Hence the change in velocity of the body is 54.55 m/s

Answer 2

The change in velocity of the body is 54.54 m/s

The velocity of the body of an object is the change of the distance of the object with time.

From the information given:

the mass of the b0dy = 11 kg

the net force F = 20 N

the time (t) = 20 s

Similarly;

Force = ma

20 = 11 ×  (a)

$\mathbf{a = \dfrac{20}{11} \ m/s^2}$

a = 1.818 m/s²

However, the acceleration of an object is the change in velocity with time.

$\mathbf{a = \dfrac{\Delta V}{t}}$

ΔV =  (a) ×  (t)

ΔV = 1.818 m/s² × 30 s

ΔV = 54.54 m/s

Learn more about the velocity of an object here:

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