Question

The velocity V of an object dropped from a tall building is given by V = V64d, where dis
the distance, in feet, the object has dropped. Find the distance when the velocity is
32 ft/sec.

Answer 1

Answer:

d = 0.0625 m

Step-by-step explanation:

The velocity of an object dropped from a tall building is given by :

$v=\sqrt{64d}$

Where

d is the distance in feet

We need to find the distance when the velocity is 32 ft/s

Rearranging for d,

$v^2=64d\\\\d=\dfrac{64}{v^2}$

Put v = 32 ft/s

$d=\dfrac{64}{32^2}\\\\d=0.0625\ m$

So, the required distance is 0.0625 m.