What is the equation of the line that passes through the points (0,4) and (3,-2)?

A. Y=2x+0
B. Y=1/2x+(-2)
C. Y=2x+4
D. Y=1/2x+4

Respuesta :

***NOTE: Please check that you wrote the numbers in the question/answer choices correctly. The answer to this problem doesn't match the answer choice. Thank you!

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

First let's find the slope (m)

The formula to find slope using two points is

[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

In this case...

[tex]y_{2} =-2\\y_{1} =4\\x_{2} =3\\x_{1} =0[/tex]

^^^Plug these numbers into the formula for slope...

[tex]\frac{-2-4}{3 - (0)}[/tex]

[tex]\frac{-6}{3}[/tex]

-2

^^^This is your slope

Here is what we have so far for the slope intercept formula:

y = -2x + b

Now we must find b

To do that you must plug in a point the line goes through in the x and y of the equation, then solve for b

For this explanation we will use the point (0,4) although you could also do it with point (3, -2) and you should get the same answer  

4 = -2(0) + b

4 = 0 + b

4 = b

NOTE: For this particular problem you wouldn't technically need to go through the steps above to find b. In this case one of the points given, (0, 4) is already the y-intercept of the line (b)

y = -2x + 4

Hope this helped!

~Just a girl in love with Shawn Mendes

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