Im not exactly sure
but you have to substitute
so
fg(x)=2x^2+1
gf(x)=(2x+1)^2
4x^2+4+2
2x^2+1=4x^2+4x+1
1=2x^2+4x+1
0=2x^2+4x+2
the solve i think
When we solve the functions fg(x)=gf(x) then we will find x=0 and x=-2.
A function is a relationship between two variables in which each values of x corresponds to the value of y.
We have been given f(x)=2x+1, g(x)=[tex]x^{2}[/tex] and we have to solve fg(x)=gf(x)
fg(x)=2[tex]x^{2}[/tex]+1
gf(x)=[tex](2x+1)^{2}[/tex]
fg(x)=gf(x)
2[tex]x^{2}[/tex]+1=[tex](2x+1)^{2}[/tex]
[tex]2x^{2} +1[/tex]=[tex]4x^{2} +4x+1[/tex]
[tex]2x^{2} +4x=0[/tex]
2x(x+2)=0
x=0,x=-2
Hence the value of x=0,-2
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