Question

Prove that
cos 9°+sin 9°/cos9°-sin9° =cot 36°
plzz fasstttt i need to writw this!!!!!!!!!​

Answer 1

Answer:

Step-by-step explanation:

LHS = (Cos9° + Sin9°) / (Cos9° - Sin9°)  

Divide by Numerator  and Denominator   by  Cos9°  

LHS = (1 + Tan9°) / (1 - Tan9°)

       = (Tan 45° + Tan 9°) / (1 - Tan 45° * Tan 9°)  

       = Tan (45°+9°)  

       = Tan 54°

       = Cot 36°

hope it helps :)