Question

discuss the diffrentiability of f(x)=(x^2-1) |x^2-x-2| +sin|x|​

Answer 1

Answer:

in:

-10

Xmax:

10

Ymin:

-10

Ymax:

10

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Because of the absolute value function |x^2 - x - 2| when this is 0 ( that is when x = 2) there will be a vertex   at the point (2, sin 2) so at this point the function is not differentiable.