A pipe is closed at one end and the air column vibrate with a fundamental note of 550Hz calculate the length of the resonating air column neglecting end correction



Respuesta :

Answer:

The length of the resonating air column is 15 cm.

Explanation:

Given;

fundamental frequency of the air column, F₀ = 550 Hz

Assume speed of sound in air, v = 330 m/s

The wavelength of the air column is calculated as;

[tex]\lambda = \frac{V}{F_o} \\\\\lambda = \frac{330}{550} \\\\\lambda = 0.6 \ m[/tex]

The  length of the resonating air column is calculated as;

In fundamental mode for closed pipe;

[tex]L = \frac{\lambda }{4} \\\\L = \frac{0.6}{4} \\\\L = 0.15 \ m\\\\L = 15 \ cm[/tex]

Therefore, the length of the resonating air column is 15 cm.