Respuesta :

Given:

[tex]\sqrt{2}=1.414[/tex]

To find:

The value of [tex]\sqrt{50}+\sqrt{72}[/tex].

Solution:

We have,

[tex]\sqrt{50}+\sqrt{72}[/tex]

It can be rewritten as

[tex]=\sqrt{2\times 25}+\sqrt{2\times 36}[/tex]

[tex]=\sqrt{2}\times \sqrt{25}+\sqrt{2}\times \sqrt{36}[/tex]        [tex][\because \sqrt{ab}=\sqrt{a}\sqrt{b}][/tex]

[tex]=5\sqrt{2}+6\sqrt{2}[/tex]

[tex]=11\sqrt{2}[/tex]

Putting [tex]\sqrt{2}=1.414[/tex], we get

[tex]=11(1.414)[/tex]

[tex]=15.554[/tex]

Therefore, the value of given expression is 15.554.

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