Question

write the rate expression for the following reaction. H2+1/2
O2 arrow H2O​

Answer 1

Answer:

$r=-k[H_2][O_2]^{1/2}$

Explanation:

Hello!

In this case, according to the chemical reaction:

H2 + 1/2  O2 --> H2O​

Since both hydrogen and oxygen are the reactants and the rate laws are written in terms of the concentration of reactants and the rate constant, we obtain:

$r=-k[H_2][O_2]^{1/2}$

Whereas the negative sign represents the consumption of those reactants and the power 1/2 the stoichiometric coefficient of oxygen in the reaction.

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