If ANQZ - ACBK, find BK. *
O BK = 39
O BK = 16
O BK = 65
O BK = 27
![If ANQZ ACBK find BK O BK 39O BK 16O BK 65O BK 27 class=](https://us-static.z-dn.net/files/dc8/563c166a9eb0886dfbc765fe04c30c49.jpg)
9514 1404 393
Answer:
(c) BK = 65
Step-by-step explanation:
Corresponding sides are proportional in similar triangles, so ...
ZT/ZQ = KF/KB
27/(2x +7) = 45/(4x+1)
27(4x+1) = 45(2x +7) . . . cross-multiply
3(4x +1) = 5(2x +7) . . . . divide by 9
12x +3 = 10x +35 . . . . . eliminate parentheses
2x = 32 . . . . . . . . . . . . . subtract 10x+3
x = 16 . . . . . divide by 2
Then the length of BK is ...
BK = 4x+1 = 4·16 +1
BK = 65