You do not need to show all of your work for this one. But be sure that you can prove your answer is correct!
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[tex]\color{plum}m∠ABC = 71° [/tex]
Which means :
m∠ABC = ∠ADC (opposite angles of a parallelogram)
m∠ABC :
= 37° + 34°
= 71°
Thus, the measure of ∠ABC = 71°
Let us find the measures of the other angles as well :
m∠BCD + m∠ADC = 180°
m∠BCD + 71 = 180°
m∠BCD = 180 - 71
m∠BCD = 109°
Thus, the measure of∠BCD = 109°
m∠BCD = ∠BAD (opposite angles of a parallelogram)
m∠BAD = 109°
Thus, the measure of ∠BAD = 109°
Therefore, m∠ABC = 71°
Answer:
Step-by-step explanation:
Given isosceles trapezoid AB = CD
Angles B and C are congruent and angles A and D are congruent.
A and B, as well as C and D sum to 180 as supplementary angles, therefore: