Question

Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable 290 m/s2 for 20 ms, then travels at constant speed for another 30 ms. During this total time of 50 ms, 1/20 of a second, how far does the tongue reach?

Answer 1

Answer:

0.232m

Explanation:

We are given that

Acceleration,$a=290m/s^2$

$t_1=20ms=20\times 10^{-3}s=0.02s$

$1ms=10^{-3}s$

$t_2=30ms=30\times 10^{-3}s=0.03s$

We have to find the distance reached by tongue.

We know that

$s=ut+\frac{1}{2}at^2$

Initial speed, u=0

Using the formula

$x_1=0+\frac{1}{2}(290)(0.02)^2$

$x_1=0.058m$

$v=u+at$

Using the formula

Speed after 0.02s

$v=0+(290)(0.02)$

$v=5.8m/s$

Distance=vt

By using the formula

Distance traveled in 0.03 s

$x_2=5.8(0.03)=0.174m$

Total distance traveled in 50 ms

$\Delta x=x_1+x_2=0.058+0.174$

=0.232m