Respuesta :
we need to bring together the terms containing x. Then constant terms on the other side. Then simplify by performing the addition/subtraction/multiplication.
Done hope it helps

Do you mean 25^(x+1) - 5^(x+1) = 100 ?
25^(x+1) - 5^(x+1) = 100
(5^2)^(x+1) - 5^(x+1) = 100
5^(2(x+1)) - 5^(x+1) = 100
5^(2(x+1)) - 5^(x+1) - 100 = 0
Quadratic Formula
5^(x+1) = [1 ± ⎷(1^2-4(1)(-100))]/[2(1)]
5^(x+1) = [1 ± ⎷401]/2
x+1 = log₅([1 + ⎷401]/2)= log₅(1 + ⎷401) - log₅(2)
x = log₅(1 + ⎷401) - log₅(2) - 1
25^(x+1) - 5^(x+1) = 100
(5^2)^(x+1) - 5^(x+1) = 100
5^(2(x+1)) - 5^(x+1) = 100
5^(2(x+1)) - 5^(x+1) - 100 = 0
Quadratic Formula
5^(x+1) = [1 ± ⎷(1^2-4(1)(-100))]/[2(1)]
5^(x+1) = [1 ± ⎷401]/2
x+1 = log₅([1 + ⎷401]/2)= log₅(1 + ⎷401) - log₅(2)
x = log₅(1 + ⎷401) - log₅(2) - 1