Need help please its my last question
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Given:
Radius of circle = 12 units
Area of sector = 24π sq. units.
Central angle = x
To find:
The value of x.
Solution:
We have,
[tex]r=12[/tex]
[tex]A=24\pi[/tex]
[tex]\theta = x[/tex]
We know that, area of a sector is
[tex]A=\dfrac{\theta }{360^\circ}\pi r^2[/tex]
Where, [tex]\theta[/tex] is central angle, r is radius.
[tex]24\pi=\dfrac{x}{360^\circ}\pi (12)^2[/tex]
[tex]24\pi=\dfrac{x}{360^\circ}\pi (144)[/tex]
[tex]\dfrac{24\pi}{144\pi}=\dfrac{x}{360^\circ}[/tex]
[tex]\dfrac{1}{6}=\dfrac{x}{360^\circ}[/tex]
Multiply both sides by 360 degrees.
[tex]\dfrac{1}{6}\times 360^\circ=x[/tex]
[tex]60^\circ=x[/tex]
The value of x is 60 degrees.
Therefore, the correct option is A.