Answer:
The volume of the right circular cone is approximately 17.9 m³
Step-by-step explanation:
The given parameters of the cone are;
Height = 17 m
Circumference of the base, C = 6.3 m
The circumference, C, of a circle is given by the formula, C = 2×π×r
Therefore, we have;
C = 6.3 m = 2×π×r
r = 6.3/(2 × π) ≈ 1.002676
The volume, V, of a cone is given by the following formula;
[tex]V = \dfrac{1}{3} \times \pi \times r^2 \times h[/tex]
Where;
r = The radius of the base ≈ 1.002676
h = The height of the cone = 17 m
[tex]V = \dfrac{1}{3} \times \pi \times 1.002676^2 \times 17[/tex]
V = 1/3 × π × (1.002676 m)² × 17 m ≈ 17.89776 m³ which by rounding up to one decimal place is 17.9 m³
The volume of the right circular cone, V ≈ 17.9 m³.
