i need help asap plz
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Answer:
y=-2/3x+3
Step-by-step explanation:
Linear equations most commonly take place in slope-intercept form:
y=mx+b
Here's what the variables mean:
y=the y-coordinate
m=the slope
x=the x-coordinate
b=the y-intercept (the point on the line that crosses the y-axis)
In a linear equation, y and x are left as y and x when m and b are replaced with numbers.
We can do this by using the formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]. We plug in any two given points: [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex].
Because it's easier to calculate with non-fractional values, we can pick the last two points: (3,1) and (6,-1).
[tex]\frac{y_2-y_1}{x_2-x_1}\\\\\frac{-1-1}{6-3}\\= \frac{-2}{3}[/tex]
Therefore, the slope of the line (m) is equal to -2/3.
So far, our equation looks like this: y=-2/3x+b.
To find the y-intercept, we take our equation y=-2/3x+b, plug in any point and solve for b. Let's use the point (3,1).
[tex]y=-\frac{2}{3}x+b\\1=-\frac{2}{3}(3)+b\\[/tex]
3 cancels out
[tex]1=-2+b\\[/tex]
Add 2 to both sides to isolate b
[tex]1=-2+b\\1+2=-2+b+2\\3=b[/tex]
Therefore, the y-intercept (b) is equal to 3.
Now, our equation looks like this: y=-2/3x+3.
I hope this helps!