Question

A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.
What are the measures of the angles in triangle ABC?
(a.) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°
(b.) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°
(c.) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
(d.) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°
plz help every time i try to do the problem my answer doesnt show up but i have no idea what im doing wrong... 
its not D tho, i know that much 

Answer 1

Answer:

c.) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

Step-by-step explanation:

A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.

What are the measures of the angles in triangle ABC?

a.) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°

b.) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°

c.) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

d.) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°

Answer 2

The measures of triangle ABC are m∠A = 73.7°,  m∠B = 16.3°  m∠C = 90°

What is a right angle triangle?

A right-angled triangle is a triangle with the largest of its angle 90° and the side facing this angle is usually called the hypotenuse.

Analysis:

side AC is the side facing the smallest angle, side BC faces the semi-largest angle and side AB faces the largest angle which is 90°.

using sine rule,

$\frac{25}{sin 90}$ = $\frac{24}{sin A}$

25 sin A = 24 sin 90

sin A = 24/25

A = arc sin(24/25) = 73.7°
$\frac{25}{sin 90}$ = $\frac{7}{sin B}$

25 sin B = 7 sin 90

sin B = 7/25

B = arc sin(7/25)  = 16.3°

In conclusion, the measures of the angles of the triangle are m∠A = 73.7°,  m∠B = 16.3°  m∠C = 90°

Learn more about right-angled triangle: brainly.com/question/18452950

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