Respuesta :
Below is the solution:
Using 2 equations:
Quantity: c + p = 10 lbs
Value::: 5.6c + 2.3p = 3.29*10 dollars
Multiply thru the Quantity Eq. by 560
Multiply thru the Value Eq. by 100
560c + 560p = 5600
560c + 230p = 3290
Subtract and solve for "p":
330p = 2310
p = 7 lbs (amt. of peanuts needed)
Solve for "c" using c+p = 10
c + 7 = 10
c = 3 lbs (amt. of cashews needed)
Using 2 equations:
Quantity: c + p = 10 lbs
Value::: 5.6c + 2.3p = 3.29*10 dollars
Multiply thru the Quantity Eq. by 560
Multiply thru the Value Eq. by 100
560c + 560p = 5600
560c + 230p = 3290
Subtract and solve for "p":
330p = 2310
p = 7 lbs (amt. of peanuts needed)
Solve for "c" using c+p = 10
c + 7 = 10
c = 3 lbs (amt. of cashews needed)
Answer: 3 pounds of cashews and 7 pounds of peanuts.
Step-by-step explanation:
Let C=cashews
Let P=peanuts
nC + (10-n)P=3.29 x 10
nC + (10-n)P=32.9
C=5.6
P=2.3
5.6n + 2.3(10-n) =32.9
5.6n + 23 - 2.3n = 32.9
3.3n = 9.9
n = 3
10 - n = 7
he needs to mix 3 pounds of cashews and 7 pounds of peanuts.