Question

the length of a rectangle is 4 in. longer than its width. If the perimeter of the rectangle is 40 in. , what is the area ?

Answer 1

Let, width = x

length = x+4

perimeter, 2(x+4+x) = 40

4x+8 = 40

4x = 32

x = 8

so, (x+4) = 8+4 = 12

so, area would be = 12 * 8 = 96 in²