Answer:
(a) Let the height of the platform is h meter,
=>By s = ut + 1/2gt^2
=>h = 0 + 1/2 x 9.8 x (2.3)^2
=>h = 25.92 m
(b) By R = [Ux] x t
=>R = 2.47 x 2.3
=>R = 5.68 m
Explanation:
Explanation:
From the exercise we know the initial horizontal velocity and the time that Janet takes to land in the water
a) Knowing the formula for free falling objects, we can calculate how high is the platform
At t=2.3m the position of Janet is y=0m
So, the platform is 26m tall
b) According to dynamics the displacement of an object can be analyze using the following formula:
So, Janet lands 6 m far from the base of the platform