Answer:
[tex]\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}[/tex]
[tex]3\sqrt{25} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}[/tex]
Step-by-step explanation:
Since we believe it
The number sequence is that those which can be described as [tex]\frac{p}{q}[/tex] and that is not ending and recurring. Figures that are unreasonable are also the ones, that are not [tex]\frac{p}{q}[/tex] and therefore are non-ending, non-recurring.
The number sequence is [tex]3\sqrt{25} = 3 \times 5 = 15[/tex]
Rational amount since it is classified as [tex]\frac{p}{q}[/tex] .[tex]\frac{-11}{151}[/tex] is really a rational number.
[tex]1.\overline{1.625}[/tex] is a real function, since it does not end but repeats it.
The rational number [tex]\sqrt {256} = 16[/tex]
Unreasonable number [tex]\sqrt{141}[/tex].
