Answer:
Partial pressure of oxygen = 90.53 torr
Explanation:
Using the formula; YO₂ = (pO₂)ⁿ / (pO₂)ⁿ + (p₅₀)ⁿ
where Y is the fraction of oxygenated myoglobin, pO₂ is the partial pressure of O₂, expressed in torr (760 torr = 1 atmosphere) and p₅₀ is the partial pressure of O₂ required to bind 50% of the myoglobin molecules, n is Hill's constant which describes the degree of cooperativity among interacting ligand sites or subunits
p₅₀ = 2.8 torr
n = 1 for myoglobin calculations since it only contains one heme group
YO₂ = 97% or 0.97
pO₂ = x
substituting the values
0.97 = x (2.8 + x)
x - 0.97x = 2.716
0.03x = 2.716
x = 2.716 / 0.03
x = 90.53 torr