Question

9
1 point
The elevator of a building can safely carry no more than 4000 lbs. A worker moves supplies in 50-Ibs boxes from the loading dock to the
fourth floor of the building. The worker weighs 210 lbs. The cart weighs 95 lbs. What is the greatest number of boxes he can move in one
trip?
1
Write an inequality and solve.
2
b choose your answer...
V
type your answer...
3
4
Next
Previous
5
6
7
8

Answer 1

Inequality: 4000= 305 + x50
Answer: 74 boxes

Explanation: To get 305 you add the weight of the cart and the weight of the worker

Then create the inequality
Subtract 305 from 4000 and you get 3695

Then since the 50 is trying to multiply against x then you do the inverse operation and divide 3695 by 50

Which equals out to 73.9 and since the point nine is higher then 5 then you round the 73 up by one which gives you 74