Respuesta :
Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
ho=2 feet
So, h(t) = -16t^2 +110t +2
Take the derivative: h'(t) = 110 -32t
The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0.
So, set h'(t)=0 and solve for t:
0 = 110 -32t
-110 = -32t
t=3.4375
t=3.44 seconds
Vo=110 feet per second
ho=2 feet
So, h(t) = -16t^2 +110t +2
Take the derivative: h'(t) = 110 -32t
The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0.
So, set h'(t)=0 and solve for t:
0 = 110 -32t
-110 = -32t
t=3.4375
t=3.44 seconds
Answer:
After 3.73 seconds ball will achieve the maximum height.
Step-by-step explanation:
Initial speed of the tennis ball is u = 120 feet per second
Since at the maximum height ball's final speed will be = 0
So we will apply the formula of motion against gravitational pull
v = u - gt
Where v = speed of the ball at maximum height
u = initial speed
g = gravitational pull = 32.17 ft/sec²
t = time to achieve maximum height
Here v = 0 so
0 = 120 - (32.17)t
t = 120/32.17 = 3.73 seconds
