-5 · (-5) + 7 = 25 + 7 = 32 → y = -5x + 7
(-5)² - (-5) + 2 = 25 + 5 + 2 = 32 → y = x² - x + 2
(-5)³ + 6 · (-5)² - (-5) + 2 = -125 + 6 · 25 + 5 + 2 = 32 → y = x³ + 6x² - x + 2
Answer:
a linear function: y = -5x + 7
a quadratic function: y = x² - x + 2
a cubic function: y = x³ + 6x² - x + 2
Thus the required functions are y = -6x+2, y = x^2+7, y = -1/5x^3+7
Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.
linear function
y = -6x+2
y = -6(-5) +2
y = 32
Quadratic function
y = x^2+7
y = (-5)^2+7
y = 32
cubic function
y = -1/5x^3+7
y=-1/5(-5)^3+7
y= 32
Thus the required functions are y = -6x+2, y = x^2+7, y = -1/5x^3+7
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