Answer:
See Explanation
Step-by-step explanation:
3.
XY is tangent at P and CP is radius
[tex] \therefore CP\perp XP\\(\because tangent\: is \: perpendicular \: to\: radius) \\\\
\therefore m\angle CPX = 90\degree \\[/tex]
4.
Radius of the circle = diameter /2 = 13/2 = 6.5.cm
5.
For BD to be be tangent to the circle with center C, BD should make right angle with radius CB.
[tex] AD^2 [/tex] should be equal to the sum of the squares BD and AB.
Let us work it out:
[tex] AD^2 = 7^2 = 49....(1)\\
AB^2 + BD^2 = 5^2 +5^2 \\
AB^2 + BD^2 = 25 + 25 \\
AB^2 + BD^2 = 50....(2) \\[/tex]
From equations (1) & (2), it is obvious that:
[tex] AD^2 \neq AB^2 + BD^2[/tex]
So, BD is not tangent to the[tex] \odot\: C. [/tex]
6.
Tangents drawn from an external point to a circle are congruent.
In circle with center C, BA and BD are tangents drawn from external point B.
Therefore,
BA = BD
x = 4
7.
In circle with center C, BA and BD are tangents drawn from external point B.
Therefore,
BD = BA (tangents drawn from external point to a circle)
x = 2
8.
In circle with center C, BA and BD are tangents drawn from external point B.
Therefore,
BA = BD (tangents drawn from external point to a circle)
2x = 10
x = 10/2
x = 5
