Answer:
The point that represents the bottom of the pool is [tex](x,y) = (-4, -16)[/tex].
Step-by-step explanation:
Given that the shape of the underground pool is a parabola, that is, a second order polynomial. Then, the point that represents the bottom of the pool is the vertex, which is contained in the standard form of the parabola. That is:
[tex]y-k = C\cdot (x-h)^{2}[/tex] (1)
Where:
[tex]x[/tex] - Independent variable, dimensionless.
[tex]y[/tex] - Dependent variable, dimensionless.
[tex]h[/tex], [tex]k[/tex] - Coordinates of the vertex, dimensionless.
[tex]C[/tex] - Constant, dimensionless.
The parabola is represented by [tex]f(x) = x^{2}+8\cdot x[/tex] and we proceed to transform into the desired form:
1) [tex]f(x) = x^{2}+8\cdot x[/tex] Given.
2) [tex]f(x) = (x^{2}+8\cdot x + 16)-16[/tex] Modulative property/Existence of the additive inverse.
3) [tex]f(x) +16 = (x+4)^{2}[/tex] Compatibility with the addition/Modulative property/Existence of the additive inverse/Perfect square trinomial.
4) [tex]y + 16 = (x+4)^{2}[/tex] Notation/Result.
Hence, the point that represents the bottom of the pool is [tex](x,y) = (-4, -16)[/tex].