Answer:
([tex]\frac{2}{3}[/tex], 2 )
Step-by-step explanation:
Given the 2 equations
3x + [tex]\frac{1}{2}[/tex] y = 3 → (1)
6x - y = 2 → (2)
Multiplying (1) by - 2 and adding to (2) eliminates the term in x, that is
- 6x - y = - 6 → (2)
Add (2) and (3) term by term to eliminate x
- 2y = - 4 ( divide both sides by - 2 )
y = 2
Substitute y = 2 into either of the 2 equations and solve for x
Substituting into (2)
6x - 2 = 2 ( add 2 to both sides )
6x = 4 ( divide both sides by 6 )
x = [tex]\frac{4}{6}[/tex] = [tex]\frac{2}{3}[/tex]
Solution is ( [tex]\frac{2}{3}[/tex], 2 )
