The final balanced equation based on the half-reactions is 3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O
What is Redox Reaction ?
Redox is a type of chemical reaction in which the oxidation states of substrate change.
Oxidation is the loss of electrons or an increase in the oxidation state of a chemical or atoms within it.
Reduction is the gain of electrons or a decrease in the oxidation state of a chemical or atoms within it
Given Equation ;
Cu + HNO₃ → Cu(NO₃)₂ + NO + H₂O
The first step is to write the oxidation numbers for each atoms in the given equation
Cu0 + H⁺¹N⁺⁵O⁻²₃ → Cu⁺²(N⁺⁵O⁻²₃)₂ + N⁺²O⁻² + H⁺¹₂O
Identify the oxidizing and reducing agent
- OXIDATION ---Cu0 → Cu⁺²(N⁺⁵O⁻²₃)₂ + 2e-
- REDUCTION---H⁺¹N⁺⁵O⁻²₃ + 3e- → N⁺²O⁻²
Balance equation in half reaction
Cu0 + 2 HNO₃ → Cu⁺²(N⁺⁵O⁻²₃)₂ + 2e-
H⁺¹N⁺⁵O⁻²₃ + 3e- → N⁺²O⁻²
Now balance the charge
Cu0 + 2HNO₃ → Cu⁺²(N⁺⁵O⁻²₃)₂ + 2e- + 2H+
H⁺¹N⁺⁵O⁻²₃ + 3e- + 3H+ → N⁺²O⁻²
Balance the oxygen atom
Cu0 + 2HNO3 → Cu+2(N+5O-23)2 + 2e- + 2H+
H+1N+5O-23 + 3e- + 3H+ → N+2O-2 + 2H2O
Make electron gain equivalent to electron lost.
3Cu0 + 6HNO3 → 3Cu+2(N+5O-23)2 + 6e- + 6H+
2H+1N+5O-23 + 6e- + 6H+ → 2N+2O-2 + 4H2O
Complete reaction
3Cu0 + 8H+1N+5O-23 + 6e- + 6H+ → 3Cu+2(N+5O-23)2 + 2N+2O-2 + 6e- + 4H2O + 6H+
Simplify the equation
3Cu0 + 8H+1N+5O-23 → 3Cu+2(N+5O-23)2 + 2N+2O-2 + 4H2O
Final equation
3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O
Learn more about Redox Reaction here ;
https://brainly.com/question/13293425
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