This question is incomplete, the complete question is;
An individual eats fish from a river contaminated with benzene. What concentrations of benzene in water (mg/L) would produce a lifetime cancer risk of 10⁻⁶ to an individual who eats 2 meals of fish per week for 30 years if the BCF for benzene is 10⁺³?
Answer:
0.021 mg/L concentration of benzene in water would produce a lifetime cancer risk 10⁻⁶ to an individual who eats 2 meals of fish per week for 30 years if the BCF for benzene is 10⁺³
Explanation:
Chronic daily intake (CDI) =(C/W) (Intake rate/ lifetime) ( Exposure)
values from EPA Exposure Factors Table)
CDI = [ (5.2 L/d × C mg/L 0.054 kg/d) / 70 kg] [30/70] [350/365]
CDI = 1.65 × 10⁻³C
Now concentration of benzene; ( RISK) = CDI × pF
= 10⁻⁶ = [2.9× 10⁻² / (MG/kg-d)] ( 1.65 × 10⁻³C)
C = 0.021 mg/L
Therefore 0.021 mg/L concentration of benzene in water would produce a lifetime cancer risk 10⁻⁶
