On moving a distance of 20m towards the foot of the cliff the angle of
elevation increases to 60° .
The situation forms 2 right angle triangle.
The height of the cliff is the opposite side of the 2 triangles formed.
Using trigonometric ratio, the bigger triangle can be represented as
follows:
tan 30 = opposite / adjacent
Let the distance from point Q to the foot of the cliff be d.
Therefore,
tan 30° = 17.3 / d
d = 17.3 / tan 30
d = 17.3 / 0.57735026919
d = 29.9644789709
d ≈ 30 m
Let's find the new angle when he moves 20 m towards the foot of the cliff.
The smaller triangle formed is used to find the new angle.
Therefore,
The new distance from the foot of the cliff (adjacent side) = 30 - 20 = 10 m
tan x° = 17.3 / 10
tan x° = 1.73
x = tan ⁻¹ 1.73
x = 59.9705982385
x ≈ 60°
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