Question

A golf ball is struck at 75 m/s at an angle of 60 degrees. What is the
horizontal velocity in m/s? (Do not state units, and give answers to the
hundredths place.) *

Answer 1

Answer:

$v_x=37.50$

Explanation:

The rectangular components of a vector $\vec v$ having a magnitude v and angle θ are:

$v_x=v\cos\theta$

$v_y=v\sin\theta$

The golf ball has an initial speed of 75 m/s at an angle of 60 degrees.

The variables of the equations have the values:

v = 75 m/s

θ = 60°

Substituting into the formula:

$v_x=75\cos 60^\circ$

$v_x=75\cdot 0.5$

$v_x=37.5~m/s$

Without specifying units and with precision to the hundredths place:

$\mathbf{v_x=37.50}$