Answer:
μ = 0.1
Explanation:
In order to keep the car on circular track, the centripetal force must be equal to the frictional force between tires and track:
Frictional Force = Centripetal Force
μmg = mv²/r
μ = v²/gr
where,
μ = coefficient of friction = ?
v = speed of car = 10 m/s
g = 9.8 m/s²
r = radius of track = 100 m
Therefore,
μ = (10 m/s)²/(9.8 m/s²)(100 m)
μ = 0.1
