Question

A motivated three legged goat accelerates at a rate of -2.67 m/s2 from a velocity of 10.8 m/s to a velocity of 3.7 m/s. How long did it take him?

Answer 1

Initial velocity (u) = 10.8 m/s

Final velocity (v) = 3.7 m/s

Acceleration (a) = -2.67 m/s²

By using equation of motion, we get:

$\bf \longrightarrow v = u + at \\ \\ \rm \longrightarrow 3.7 = 10.8 + ( - 2.67)t \\ \\ \rm \longrightarrow 10.8 - 2.67t = 3.7 \\ \\ \rm \longrightarrow (10.8 - 10.8) - 2.67t = 3.7 - 10.8 \\ \\ \rm \longrightarrow - 2.67t = - 7.1 \\ \\ \rm \longrightarrow \dfrac{ - 2.67}{ - 2.67} t = \dfrac{ - 7.1}{ - 2.67} \\ \\ \rm \longrightarrow t = 2.6 \: s$

$\therefore$ Time taken (t) = 2.6 s