Answer:
[tex]-121.56\ \text{J}[/tex]
Explanation:
[tex]V_1[/tex] = Initial volume = 0.2 L
[tex]V_2[/tex] = Final volume = 0.6 L
P = Pressure = 3 atm
[tex]W=-P\Delta V\\\Rightarrow W=-3(V_2-V_1)\\\Rightarrow W=-3(0.6-0.2)\\\Rightarrow W=-1.2\ \text{L atm}[/tex]
[tex]1\ \text{L atm}=101.3\ \text{J}\\\Rightarrow -1.2\ \text{L atm}=-1.2\times 101.3\ \text{J}=-121.56\ \text{J}[/tex]
Work done is [tex]-121.56\ \text{J}[/tex].