Calculate the work when a cylinder equipped with a piston changes volume from 0.200 L to 0.600 L against an external pressure of 3.00 atm (Remember that 101.3 J = 1 L∙atm)

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Answer:

[tex]-121.56\ \text{J}[/tex]

Explanation:

[tex]V_1[/tex] = Initial volume = 0.2 L

[tex]V_2[/tex] = Final volume = 0.6 L

P = Pressure = 3 atm

[tex]W=-P\Delta V\\\Rightarrow W=-3(V_2-V_1)\\\Rightarrow W=-3(0.6-0.2)\\\Rightarrow W=-1.2\ \text{L atm}[/tex]

[tex]1\ \text{L atm}=101.3\ \text{J}\\\Rightarrow -1.2\ \text{L atm}=-1.2\times 101.3\ \text{J}=-121.56\ \text{J}[/tex]

Work done is [tex]-121.56\ \text{J}[/tex].

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