Question

A rectangle has a length of 5.50 m and a width of 12.0 m. What are the perimeter and area of this rectangle?

Answer 1

Answer: The perimeter and area of the given rectangle is 35 m and $66m^2$ respectively.

Explanation:

To calculate the perimeter of rectangle, we use the equation:

$\text{Perimeter}=2(l+b)$

where,

l = length of the rectangle = 5.50 m

b = breadth of the rectangle = 12.0 m

Putting values in above equation, we get:

$\text{Perimeter of rectangle}=2(5.50+12)\\\\\text{Perimeter of rectangle}=35m$

To calculate the area of the rectangle, we use the equation:

$\text{Area}=l\times b$

Putting values in above equation, we get:

$\text{Area of rectangle}=5.50\times 12\\\\\text{Area of rectangle}=66m^2$

Hence, the perimeter and area of the given rectangle is 35 m and $66m^2$ respectively.

Answer 2

a. The perimeter of the rectangle is 35 meters.

b. The area of the rectangle is 66 square meters.

Given the following data:

• Length of rectangle = 5.50 meters.

• Width of rectangle = 12.0 meters.

a. To find the perimeter of the rectangle:

Mathematically, the perimeter of a rectangle is given by the formula;

$P = 2(L + W)$

Substituting the values into the formula, we have;

$Perimeter = 2(5.5 + 12)\\\\Perimeter = 2(17.5)$

Perimeter = 35 meters.

b. To find the area of the rectangle:

Mathematically, the area of a rectangle is given by the formula;

$Area = LW$

Substituting the values into the formula, we have;

$Area = 5.5(12)$

Area = 66 square meters.

Find more information: brainly.com/question/897975