Question

A gas-forming reaction produces 1.95 m3 of gas against a constant pressure of 196.0 kPa. Calculate the work done by the gas in joules.

Answer 1

Answer:

Work done W = -382,206 J (Approx)

Explanation:

We know that;

1 atm = 101.32 kPa

1 L-atm = 101.325 J

1 m³ = 1,000 L

Computation:

Work done W = -P∆V

Pressure = 196 kPa × (1 / 101.32 kPa)

Pressure = 1.9344 atm

∆V = 1.95 × (1000 L) = 1,950 L

So,

W = -(1.9344 atm) × (1,950 L)

W = -3772.0 L-atm

Work done W = -3772.0 L-atm × (101.325 J / 1 L.atm)

Work done W = -382,206 J (Approx)

Answer 2

The work done by the gas in Joules is equal to 3,763.5‬ Joules.

Given the following data:

• Pressure = 196.0 kPa.

• Volume = 1.95 $m^3$

Conversion:

1 atm = 101.325

X atm = 196.0 kPa

X = $\frac{196.0}{101.325} = 1.93\; atm$

Conversion:

1 $m^3$ = 1000 Liter

1.95 $m^3$ = 1950 Liter

To calculate the work done by the gas in Joules:

Mathematically, the work energy by a system is given by the formula:

$Work = P \delta V$

Where:

• P is the pressure.

• V is the volume.

Substituting the parameters into the formula, we have

$Work\;energy = 1.93 \times 1950$

Work energy = 3,763.5‬ Joules.

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