Respuesta :

[tex]f(x)=3x+2\\The\ domain\ D_f=\mathbb{R}\\\\g(x)=x^2+1\\The\ domain\ D_G=\mathbb{R}\\\\D_f=D_g\ therefore\ (f\times g)(x)=f(x)\times g(x)\\\\(f\times g)(x)=(3x+2)(x^2+1)=3x^3+3x+2x^2+2=\boxed{3x^3+2x^2+3x+2}[/tex]

Answer:

[tex](f\times g) (x)=3x^3+2x^2+3x+2[/tex]            

Step-by-step explanation:

Given : If [tex]f(x) = 3x + 2[/tex] and [tex]g(x)=x^2+1[/tex]

To find : Which expression is equivalent to [tex](f\times g) (x)[/tex]?

Solution :  

We can write,

[tex](f\times g) (x)=f(x)\times g(x)[/tex] ....(1)

We know, [tex]f(x) = 3x + 2[/tex] and [tex]g(x)=x^2+1[/tex]

Substituting the values in (1),

[tex](f\times g) (x)=(3x+2)\times (x^2+1)[/tex]

Multiply term by term,

[tex](f\times g) (x)=3x^3+3x+2x^2+2[/tex]

[tex](f\times g) (x)=3x^3+2x^2+3x+2[/tex]

Therefore, The expression is equivalent to  [tex](f\times g) (x)=3x^3+2x^2+3x+2[/tex]

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