Question

Two resistors of 12Ω and 2Ω are connected in parallel to a battery of 4 V. Current through 12Ω resistor will be _____________ and power dissipated at 2Ω resistor will be ??​

Answer 1

Answer:

0.33  Amp

8 Watts

Explanation:

The current through the 12 Ω resistor will be given by Ohm's law:

4 V / 12 Ω = 1/3 Amp ≈ 0.33  Amp

The power dissipated on the 2 Ω resistor can be calculated via the formula: $\frac{V^2}{R}$  which gives:

4^2 / 2 = 8 Watts