Respuesta :
Answer:
Step-by-step explanation:
five chips are chosen at random and without replacement from a population of 40 chips
First 3 chips match mine
As selection is without replacement,remaining population is 40-3=37
Remaining number of selections to be made=5-3=2
Number of possible way the two numbers can be selected is given by computing combinations without replacement.
Number of possible combinations=37!/(37-2)!2! =666
My chances=1/666=1.5*10^-3
Answer:
0.002
Step-by-step explanation:
The order of choosing the 5 chips without replacement from a population of 40 chips does not matter, so I decide to choose 3 chips first which match the winning numbers
Number of chips left = 40 - 3 = 37, number of chips left to be chosen = 5 - 3 = 2
The number of ways to choose the remaining 2 chips from the 37 chips left can be done by the combination method
Number of ways = n combination r = n!/(n - r)!r!
n = 37, r = 2
Number of ways = 37!/(37-2)!2! = 37!/35!2! = 37×36×35!/35!×2 = 37×36/2 = 37×18 = 666
My chances of winning = 1/666 = 0.002