Answer:
P(X≤5) = 0.5105 (Approx)
Step-by-step explanation:
Assume, x = completion time of given task
Mean u = 7
So,
λ = 1/u = 1/7
So,
x ↔ exp(λ)
f(x) = P(X≤x) = [tex]1-e^{-\frac{1}{u}x }[/tex]
P(X≤5) = [tex]1-e^{-\frac{1}{7}5 }[/tex]
P(X≤5) = 0.5105 (Approx)