Question

A sample of an ideal gas has a volume of 2.29 L at 285 K and 1.12 atm. Calculate the pressure when the volume is 1.33 L and the temperature is 302 K.

Answer 1

Answer:

$P_2=2.04atm$

Explanation:

Hello.

In this case, by using the combined ideal gas law, we can identify the change in pressure, temperature an volume as shown below:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

In such a way, since we are asked to compute the final pressure, P2, we proceed as follows:

$P_2=\frac{P_1V_1T_2}{T_1V_2} \\\\P_2=\frac{1.12atm*2.29L*302K}{285K*1.33L}\\ \\P_2=2.04atm$

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