Question

g Benton Industries manufactures carpets and draperies in the Atlanta area. Employee absenteeism was becoming a problem, so HR conducted a study involving a random sample of employees. The number of absences during the past year was tabulated by marital status. What is the probability that an employee is not married and has between 1 and 5 absences in the past year

Answer 1

Answer:

The probability that an employee is not married and has between 1 and 5 absences in the past year is 0.204.

Step-by-step explanation:

The probability of an event, say E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n (E)}{N}$

The number of absences during the past year tabulated by marital status is as follows:

Marital Status      0 Absences     1 - 5 Absences     More than 5 Absences

  Married                     100                     98                              52

Not Married                  77                     102                              71

Compute the probability that an employee is not married and has between 1 and 5 absences in the past year as follows:

$P(\text{NM}\cap 1-5\ \text{Absences})=\frac{n(\text{NM}\cap 1-5\ \text{Absences})}{N}$

                                       $=\frac{102}{100+98+52+77+102+71}\\\\=\frac{102}{500}\\\\=0.204$

Thus, the probability that an employee is not married and has between 1 and 5 absences in the past year is 0.204.