Question

What volume of 0.100 M AgNO3 is
needed to react completely with
45.0 mL of 0.230 M Na2S?
2AgNO3 + Na2S → Ag2S + 2NaNO3
[?] mL AgNO3

Answer 1

Answer:

448mL AgNO3

Explanation:

M x V

n = 0.230 x .045 = 0.01

2AgNO3 + Na2S --> Ag2S+2NaNO3

1 mol Ag2S --> 2 moles AgNO3

.01 mol Ag2S --> ? moles AgNO3

.01x2/1=.02 moles AgNO3

Moles to L conversion is multiplying by 22.4L so we do .02 x 22.4=0.448L

Then we convert to mL so we multiply by 1000 (1000 x 0.448)

448mL AgNO3

There you go friend, good luck with chemistry :)