Answer:
The current is [tex]I = 6.59*10^{-5} \ A[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 5.48*10^{5} \ m/s[/tex]
The radius is [tex]r = 2.12 *10^{-10} \ m[/tex]
Generally the period of the orbiting electron is mathematically represented as
[tex]T = \frac{2 \pi * r }{v}[/tex]
=> [tex]T = \frac{2 * 3.142 * 2.12 *10^{-10} }{ 5.48 *10^{5}}[/tex]
=> [tex]T = 2.43 *10^{-15} \ s[/tex]
Gnerally the effective current associated with this orbiting electron
[tex]I = \frac{e}{T}[/tex]
Here e is the charge on an electron with value [tex]e = 1.60 *10^{-19} \ C[/tex]
So
[tex]I = \frac{1.60 *10^{-19}}{2.43 *10^{-15}}[/tex]
=> [tex]I = 6.59*10^{-5} \ A[/tex]
