Question

Five years ago, Charlie was twice older than Priya. What are their ages now if in 3 years the sum of their ages will be 76?
Tysm!

Answer 1

Answer:

present age of charlie is  45 years

present age of priya is  25 years

Step-by-step explanation:

Let start from five years ago

Let at that age of Priya was x years

given that

Charlie was twice older than Priya

age of Charlie = 2x

_____________________________________________

present age of charlie = age 5 years ago + 5 years = 2x + 5

present age of priya = age of priya  5 years ago + 5 years x + 5 = x + 5

_________________________________________________

age of charlie 3 years from now = present age of charlie + 3 years

age of charlie 3 years from now =2x + 5 + 3 = 2x + 8

age of priya 3 years from now = present age of priya + 3 years

age of priya 3 years from now =x + 5 + 3 = x + 8

Given that

in 3 years the sum of their ages will be 76

thus

sum of their ages in 3 years from now = x + 8 + 2x + 8 = 76

=> 3x + 16 = 76

=> 3x = 76-16 = 60

=> x = 60/3 = 20

Thus,

present age of charlie =  2x + 5 = 2*20 + 5 = 45 years

present age of priya = x + 5 = 20 + 5 = 25 years

Answer 2

The present ages of Charlie and Priya are 45 and 25 respectively.

Important information:

• Five years ago, Charlie was twice older than Priya.
• In 3 years the sum of their ages will be 76.

We need to find their ages.

System of equations:

Let the present area of Charlie be $x$ and the present age of Priya be $y$. So, five years age their age was $x-5$ and $y-5$ respectively.

$x-5=2(y-5)$

$x-5=2y-10$

$x=2y-10+5$

$x=2y-5$         ...(i)

After three years age their age will be $x+3$ and $y+3$ respectively.

$x+3+y+3=76$     ...(ii)

$(2y-5)+y+6=76$

$3y+1=76$

$3y=75$

Divide both sides by 3.

$y=25$

Substitute this in (i).

$x=2(25)-5$

$x=50-5$

$x=45$

Therefore, the present ages of Charlie and Priya are 45 and 25 respectively.

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