[tex] \frac{3}{x + 4 } = \frac{4}{2x + 2} [/tex]
[tex]x + 4 \times 4 = 2 x + 2 \times 3[/tex]
[tex]4x + 16= 6x + 6[/tex]
[tex]6x = 4x + 16 - 6[/tex]
[tex]6x = 4x + 10[/tex]
[tex]4x - 10 = 6x[/tex]
[tex]10 = 6x - 4x[/tex]
[tex]10 = 2x[/tex]
[tex]x = \frac{10}{2} [/tex]
[tex]x = 5[/tex]
Using this let us find the two proportional fractions .
[tex] = \frac{3}{x + 4} [/tex]
[tex] = \frac{3}{5 + 4} [/tex]
[tex] = \frac{3}{9} [/tex]
[tex] = \frac{4}{2x + 2} [/tex]
[tex] = \frac{4}{10 + 2} [/tex]
[tex] = \frac{4}{12} [/tex]
∴the proportional fractions are =
3/4 :: 9/12