Question

the sum of two fractions is 9 1^4 their difference is 3 1^8, what are the two fractions?​

Answer 1

Answer:

$6\frac{3}{16}~,~3\frac{1}{16}$

Step-by-step explanation:

let the fractions be x and y,then

$x+y=9\frac{1}{4}=\frac{37}{4}=\frac{74}{8}\\x-y=3\frac{1}{8}=\frac{25}{8}\\adding\\2x=\frac{74}{8}+\frac{25}{8}=\frac{99}{8}\\x=\frac{99}{16}=6\frac{3}{16}\\again ~subtracting\\2y=\frac{74}{8}-\frac{25}{8}=\frac{49}{8}\\y=\frac{49}{16}=3\frac{1}{16}$