[tex]\large\underline{\underline{\red{\sf \blue{\longmapsto} Step-by-step\: Explanation:-}}}[/tex]
Given linear equⁿ : x - 2y = 6 .
So , on drawing its graph , the points though which it passes , the coordinates of that particular point will be a solution for this linear equⁿ .
Here , taking the given equⁿ & drawing its graph ,
⇒ x - 2y = 6 .
⇒ x = 6 + 2y .
Now , for a given value of y , x will also have some values .
[tex]\boxed{\begin{tabular}{|c|c|c|}\cline{1-3} \bf x & 6 & 8 \\ \cline{1-3} \bf y & 0 & 1 \\\cline{1-3} \end{tabular}}[/tex]
Now , it's clear that the required order pair which will be solution of the equⁿ can be ( 6 , 0 ) or ( 8 , 1 ) . But since it is a straight line it will have infinite number of solutions .
[ Also Refer to graph in the attachment ]
The ordered pair which will be the solution of the equation can be ( 6, 0 ) or ( 8, 1 ).
Given that,
Equation; [tex]\rm x-2y =6[/tex]
We have to determine,
An ordered pair (x, y) is a solution to the equation?
According to the question,
An ordered pair refers to a number written in a certain order. An ordered pair is used to show the position on a graph,
Where the "x" (horizontal) value is first, and the "y" (vertical) value is second. Also in the co-ordinate system, ordered pair is used to locate a point.
The points through which it passes, the coordinates of that particular point will be a solution for this linear equation.
Here, taking the given equation & drawing its graph,
Equation; [tex]\rm x-2y =6[/tex]
The equation can also be written as,
[tex]\rm x-2y =6\\\\x = 6+2y[/tex]
An ordered pair of the solution is found when substitute y = 0,
[tex]\rm x = 6+2y \\\\x= 6+2(0)\\\\x = 6+0\\\\x = 6[/tex]
And another ordered pair of the solution is found when substitute y = 1,
[tex]\rm x = 6+2y \\\\x= 6+2(1)\\\\x = 6+2\\\\x = 8[/tex]
Hence, the required order pair which will be the solution of the equation can be ( 6, 0 ) or ( 8, 1 ).
For more details refer to the link given below.
https://brainly.com/question/12926248
